最近我一直在努力学习ASP.NET.我已经浏览了ASP.NET网站上的教程,但在大多数情况下,我是一个完整的初学者.我也一直致力于创建一个个人网站,我选择使用CMS Umbraco,因为它基于ASP.NET.
现在我的问题并不是特定于ASP或Umbraco.它可以应用于PHP和Drupal或任何其他网站框架和CMS.我想知道何时以及为什么要使用现有的CMS技术(Umbraco,Drupal等)创建网站,以及何时应该使用像ASP.NET这样的基础Web应用程序框架从"临时"创建网站, PHP,JSP等..
我在使用std :: string :: find()时遇到了麻烦.我通过以下代码从控制台读取字符串:
50 while(command.find(exitString) != 0) {
51 std::cout << "$ ";
52 getline(std::cin, command);
53
54 doSwitch(command);
55 }
然后我通过以下功能"切换"它们:
59 void Console::doSwitch(std::string command) {
60 if(command.find(helpString) == 0) {
61 help();
62 } else if(command.find(loadString) == 0) {
63 try {
64 doLoad(command);
65 } catch(std::string str) {
66 std::cout << str << std::endl;
67 }
68 } else if(command.find(dumpProcString) == 0) {
69 try {
70 doDumpProc(command);
71 } catch(std::string str) {
72 std::cout …我有这个代码:
number = 2
size = 5
list_b = [("b","b","b")]
list_a = [("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a")]
for i in range(number):
list_a.insert(size,list_b)
print list_a
它给了我这个:
[('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('b', 'b', 'b'),
('b', 'b', 'b'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', …假设我已经尽力编写安全代码:sql注入数据库并不容易,输出是从xss和其他来过滤的.接下来的问题是如何跟踪有人试图破解网站的问题.开发人员可以做些什么并不会让他们阅读来自他们网站的每个URL请求的日志？(不是我甚至不知道该怎么做).
我使用PHP,因此欢迎特定于PHP的工具或答案.
我为一个简单的视图创建了一个"而不是"触发器,该视图只对表上的select*和不执行任何操作的触发器(我想最小化问题):
create or replace view tmp(id, nazwa, nip, adres, zalega, punkty) as
select * from klient
create or replace trigger tmp_trg
instead of insert
on tmp
for each row
begin
end;
视图已创建.然后,当我想要声明此触发器时,sql developer返回错误:
错误(8,1):PLS-00103:当遇到以下情况之一时遇到符号"END":如果循环mod为空pragma raise返回选择更新,则使用'一个标识符''双引号开始情况声明退出goto delimited-identifier''绑定变量'<< close current delete fetch lock insert open rollback savepoint set sql execute commit forall merge pipe
printf/puts等_("hello,world \n")参数的作用是什么？我经常在阅读GNU源代码时发现它.
这是我的脚本,计算今天圣何塞的日出时间,但如果我想明天得到它,我该怎么办呢？
<?php
//San Jose, CA
$lat = 37.339386; // North
$long = -121.894955; // East
$offset = -8; // difference between GMT and local time in hours
$zenith=90+50/60;
echo "<br><p>Sunrise: ".date_sunrise(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
echo "<br>Sunset: ".date_sunset(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
?>
我正在尝试在python中编写脚本以将utf-8文件转换为ASCII文件:
#!/usr/bin/env python
# *-* coding: iso-8859-1 *-*
import sys
import os
filePath = "test.lrc"
fichier = open(filePath, "rb")
contentOfFile = fichier.read()
fichier.close()
fichierTemp = open("tempASCII", "w")
fichierTemp.write(contentOfFile.encode("ASCII", 'ignore'))
fichierTemp.close()
当我运行此脚本时,我有以下错误:
在范围序数不(128):UnicodeDecodeError错误:0xef在位置13"ASCII"编解码器不能解码的字节
我认为可以忽略编码方法中的ignore参数的错误.但似乎没有.
我对其他转换方式持开放态度.
在使用C++迭代器进行编码时,如果你想获得迭代器指向的前一个值,你会写:
*--Iter
或者你认为最好添加括号如下:
*(--Iter)
？
我有两个HashMap对象定义如下:
HashMap<String, Integer> map1 = new HashMap<String, Integer>();
HashMap<String, Integer> map2 = new HashMap<String, Integer>();
我还有第三个HashMap对象:
HashMap<String, Integer> map3;
我该如何合并map1,并map2汇集成map3？