我在INNODB/MySQL表中声明了一个字段
VARCHAR(255) CHARACTER SET utf8 NOT NULL
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但是当插入我的数据被截断为255字节而不是字符.这可能会破坏尾随的两个咬合代码点,我强调文本 n两个留下一个无效的字符.任何想法我可能做错了什么
编辑:
示例会话是这样的
mysql> update channel set comment="????????????????????????????? ??????????????????????????????????????????????????????????????????????????????x" where id = 1;
Query OK, 0 rows affected, 1 warning (0.00 sec)
Rows matched: 1 Changed: 0 Warnings: 1
mysql> select id, channelName, comment from channel;
+----+-------------+------------------------------------------------------------------------------------------
| id | channelName | comment |
+----+-------------+-----------------------------------------------------------------------------------------
| 1 | foo | ????????????????????????????? ????????????????????????????????????????????????????????? |
+----+-------------+-----------------------------------------------------------------------------------------
1 row in set (0.00 sec)
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通过mysql-admin我查看注释字段,看看它确实是VARCHAR(255)并使用"UTF-8 Unicode"
从命令
show full columns from channel
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我明白了
+-----------------------------+------------------+-----------------+------+-----+---------+----------------+---------------------------------+---------+
| …Run Code Online (Sandbox Code Playgroud) 将字符串拆分成单词的正确方法是什么?(字符串不包含任何空格或标点符号)
例如:"stringintowords" - >"String into Words"
你能告诉我这里应该使用什么算法吗?
!更新:对于那些认为这个问题仅仅是为了好奇的人.该算法可用于动态域名("sportandfishing .com" - >"SportAndFishing .com"),此算法目前由aboutus dot org用于动态执行此转换.
algorithm nlp dynamic-programming string-split text-segmentation
我正在尝试使用基本身份验证进行测试签名.我尝试过几种方法.请参阅下面的代码,了解失败尝试和代码的列表.有什么明显的我做错了.谢谢
class ClientApiTest < ActionController::IntegrationTest
fixtures :all
test "adding an entry" do
# No access to @request
#@request.env["HTTP_AUTHORIZATION"] = "Basic " + Base64::encode64("someone@somemail.com:qwerty123")
# Not sure why this didn't work
#session["warden.user.user.key"] = [User, 1]
# This didn't work either
# url = URI.parse("http://localhost.co.uk/diary/people/1/entries.xml")
# req = Net::HTTP::Post.new(url.path)
# req.basic_auth 'someone@somemail.com', 'qwerty123'
post "/diary/people/1/entries.xml", {:diary_entry => {
:drink_product_id => 4,
:drink_amount_id => 1,
:quantity => 3
},
}
puts response.body
assert_response 200
end
end
Run Code Online (Sandbox Code Playgroud) 我有一个文本框和许多按钮.当用户在某个文本框中并按下"输入"键时,将引发特定的按钮单击事件.我在互联网上看到"输入"键有一些问题,我尝试了一些解决方案但仍然总是进入该按钮事件(该按钮是页面中的第一个按钮).
我尝试创建一个什么都不做的按钮,并在page_load中写这个:
idTextBoxFA.Attributes.Add("onkeydown","if(event.which || event.keyCode){if ((event.which == 13) || (event.keyCode == 13)) {document.getElementBtId('" + noEnterButton.UniqueID + "').click();return false;}} else {return true}; ");
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我的所有页面控件都在一个表单中,我尝试将表单"defaultButton"赋予我创建的那个按钮.那也没有用.
知道为什么这不起作用,我做错了什么?
这是我的阵列:
$arr = array(-3, -4, 1, -1, 2, 4, -2, 3);
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我想这样排序:
1
2
3
4
-1
-2
-3
-4
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因此,首先会有从最低值到最高值排序的值大于零的值,然后会有从最高值到最低值排序的负值.
有一些优雅的方式来做到这一点?
我一直在查看HTML 5样板模板(来自http://html5boilerplate.com/),并注意到"?v=1"在引用CSS和Javascript文件时使用URL.
"?v=1"在链接和脚本标记中附加到CSS和Javascript URL的作用是什么?"?v=1"(示例来自以下示例:) js/modernizr-1.5.min.js.有这样的原因吗?来自他们的样本index.html:
<!-- CSS : implied media="all" -->
<link rel="stylesheet" href="css/style.css?v=1">
<!-- For the less-enabled mobile browsers like Opera Mini -->
<link rel="stylesheet" media="handheld" href="css/handheld.css?v=1">
<!-- All JavaScript at the bottom, except for Modernizr which enables HTML5 elements & feature detects -->
<script src="js/modernizr-1.5.min.js"></script>
<!------ Some lines removed ------>
<script src="js/plugins.js?v=1"></script>
<script src="js/script.js?v=1"></script>
<!--[if lt IE 7 ]>
<script src="js/dd_belatedpng.js?v=1"></script>
<![endif]-->
<!-- yui profiler …Run Code Online (Sandbox Code Playgroud) 我有以下C代码从管道读取然后应该阻止但它永远不会阻止
int pipe_fd;
int res;
int open_mode = O_RDONLY;
char buf[100];
int bytes_read = 0;
memset (buf, '\0', sizeof(buf));
pipe_fd = open(FIFO_NAME, open_mode);
if (access(FIFO_NAME, F_OK) == -1)
{
res = mkfifo(FIFO_NAME, 0777);
if (res != 0)
{
fprintf (stderr, "Could not create fifo %s\n", FIFO_NAME);
exit (EXIT_FAILURE);
}
}
for(;;)
{
do
{
res = read(pipe_fd, buf, sizeof(buf));
bytes_read += res;
}while (res > 0);
// process data then go back and block
............
}
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它通过bash脚本中的某些代码发送一个简单的缓冲区,例如'./test 1'
#!/bin/bash
pipe=/tmp/pipe …Run Code Online (Sandbox Code Playgroud) 我正在为计费工具创建一个应用程序.我希望使用右对齐显示金额列.如何为JTable列设置正确的对齐方式?
我收到这个错误
`establish_connection': Please install the mysql2 adapter: `gem install activerecord-mysql2-adapter` (no such file to load -- active_record/connection_adapters/mysql2_adapter) (RuntimeError)
from /opt/ruby-enterprise-1.8.7-2010.02/lib/ruby/gems/1.8/gems/activerecord-
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这是整个错误和我的配置和gemfile的转储.
我不想使用[ExpectedException(ExceptionType = typeof(Exception),ExpectedMessage ="")]而是希望在我的方法中包含异常.我能这样做吗?请举个例子.
谢谢