如果以 0 结果退出，如何退出所有主管进程

Question

我用这样的主管运行 docker 容器：

文件

CMD ["/run.sh"]

运行文件

#!/usr/bin/env bash
exec supervisord -n

主管-serf.conf

[group:job]
programs=serf,producer

[program:serf]
command=/start-serf-agent.sh
numprocs=1
autostart=true
autorestart=unexpected
stopasgroup=true
killasgroup=true
stdout_logfile=/dev/stdout
stdout_logfile_maxbytes=0
stderr_logfile=/dev/stderr
stderr_logfile_maxbytes=0

start-serf-agent.sh

#!/bin/bash
exec serf agent --join=serf:7946 -tag role=producer

supervisor-service.conf

[program:producer]
command=/start.sh
numprocs=1
stopasgroup=true
killasgroup=true
stdout_logfile=/dev/stdout
stdout_logfile_maxbytes=0
stderr_logfile=/dev/stderr
stderr_logfile_maxbytes=0

启动文件

#!/bin/bash
exec /producer --project=${NAME}

制作人停止后，我得到了：

producer_1 |     2016/02/29 21:59:50 [INFO] serf: EventMemberLeave: 7c4fbc80af97 172.19.0.2
producer_1 | 2016/02/29 21:59:51 INF    1 stopping
producer_1 | 2016/02/29 21:59:51 INF    1 exiting router
producer_1 | 2016-02-29 21:59:51,281 INFO exited: producer (exit status 0; expected)
producer_1 |     2016/02/29 21:59:51 [INFO] agent: Received event: member-leave

但是 serf-agent 保持容器处于运行状态。当生产者以状态 0 正常完成他的工作时，我想停止 Docker 容器。我试图将进程加入一个组，但似乎不起作用。伙计们，我跳过了什么？请帮帮我！

Answer 1

我解决了主管eventlistener 的问题：

[program:worker]
command=/start.sh
priority=2
process_name=worker
numprocs=1
stopasgroup=true
killasgroup=true
stdout_logfile=/dev/stdout
stdout_logfile_maxbytes=0
stderr_logfile=/dev/stderr
stderr_logfile_maxbytes=0

[eventlistener:worker_exit]
command=/kill.py
process_name=worker
events=PROCESS_STATE_EXITED

杀死.py

#!/usr/bin/env python
import sys
import os
import signal

def write_stdout(s):
   sys.stdout.write(s)
   sys.stdout.flush()
def write_stderr(s):
   sys.stderr.write(s)
   sys.stderr.flush()
def main():
   while 1:
       write_stdout('READY\n')
       line = sys.stdin.readline()
       write_stdout('This line kills supervisor: ' + line);
       try:
               pidfile = open('/var/run/supervisord.pid','r')
               pid = int(pidfile.readline());
               os.kill(pid, signal.SIGQUIT)
       except Exception as e:
               write_stdout('Could not kill supervisor: ' + e.strerror + '\n')
       write_stdout('RESULT 2\nOK')
if __name__ == '__main__':
   main()
   import sys
main issue I forgot to point to **process_name**

docker 容器中的好文章流程管理

Answer 2

这是一个稍微简化的版本，它使用 shell 脚本而不是 python 脚本，并且还涵盖多个服务，如果其中一个失败，则杀死整个主管。

配置文件

$ cat /etc/supervisord.conf
[supervisord]
nodaemon=true
loglevel=debug
logfile=/var/log/supervisor/supervisord.log
pidfile=/var/run/supervisord.pid
childlogdir=/var/log/supervisor

[program:service1]
command=/usr/sbin/service1
user=someone
autostart=true
autorestart=true
startsecs=30
process_name=service1

[program:service2]
command=/usr/sbin/service2
user=root
autostart=true
autorestart=true
startsecs=30
process_name=service2

[eventlistener:processes]
command=stop-supervisor.sh
events=PROCESS_STATE_STOPPED, PROCESS_STATE_EXITED, PROCESS_STATE_FATAL

stop-supervisor.sh

$ cat stop-supervisor.sh
#!/bin/bash

printf "READY\n";

while read line; do
  echo "Processing Event: $line" >&2;
  kill -3 $(cat "/var/run/supervisord.pid")
done < /dev/stdin

参考

• Docker 容器中的进程管理
• 如果任何子进程失败，则杀死主管