如何在 Windows Powershell 中区分两个文件夹？

Question

我正在尝试使用 Windows Powershell 查找两个文件夹结构的内容差异。我使用了以下方法来确保文件名相同，但是此方法不会告诉我文件的内容是否相同：

$firstFolder = Get-ChildItem -Recurse folder1
$secondFolder = Get-ChildItem -Recurse folder2
Compare-Object -ReferenceObject $firstFolder -DifferenceObject $secondFolder

此 ServerFault 问题中描述的技术适用于比较单个文件，但这些文件夹包含数百个不同深度的文件。

解决方案不一定需要告诉我文件中的具体内容不同 - 只是它们是不同的。我对元数据的差异不感兴趣，例如日期，我已经知道它们是不同的。

Answer 1

如果要将比较包装到循环中，我将采用以下方法：

$folder1 = "C:\Users\jscott"
$folder2 = "C:\Users\public"

# Get all files under $folder1, filter out directories
$firstFolder = Get-ChildItem -Recurse $folder1 | Where-Object { -not $_.PsIsContainer }

$firstFolder | ForEach-Object {

    # Check if the file, from $folder1, exists with the same path under $folder2
    If ( Test-Path ( $_.FullName.Replace($folder1, $folder2) ) ) {

        # Compare the contents of the two files...
        If ( Compare-Object (Get-Content $_.FullName) (Get-Content $_.FullName.Replace($folder1, $folder2) ) ) {

            # List the paths of the files containing diffs
            $_.FullName
            $_.FullName.Replace($folder1, $folder2)

        }
    }   
}

请注意，这将忽略在 $folder1和 中都不存在的文件$folder2。

Answer 2

我已经对 jscott 的回答进行了扩展，以输出存在于一个而不是另一个中的文件，供那些对这种类型的功能感兴趣的人使用。请注意，它也显示了取得的进展，因为我很难看到那些巨大的文件夹，但差异并不大。看起来剧本是挂在我身上的。这是用于此的powershell代码：

$folder1 = "C:\Folder1"
$folder2 = "C:\Folder2"

# Get all files under $folder1, filter out directories
$firstFolder = Get-ChildItem -Recurse $folder1 | Where-Object { -not $_.PsIsContainer }

$failedCount = 0
$i = 0
$totalCount = $firstFolder.Count
$firstFolder | ForEach-Object {
    $i = $i + 1
    Write-Progress -Activity "Searching Files" -status "Searching File  $i of     $totalCount" -percentComplete ($i / $firstFolder.Count * 100)
    # Check if the file, from $folder1, exists with the same path under $folder2
    If ( Test-Path ( $_.FullName.Replace($folder1, $folder2) ) ) {
        # Compare the contents of the two files...
        If ( Compare-Object (Get-Content $_.FullName) (Get-Content $_.FullName.Replace($folder1, $folder2) ) ) {
            # List the paths of the files containing diffs
            $fileSuffix = $_.FullName.TrimStart($folder1)
            $failedCount = $failedCount + 1
            Write-Host "$fileSuffix is on each server, but does not match"
        }
    }
    else
    {
        $fileSuffix = $_.FullName.TrimStart($folder1)
        $failedCount = $failedCount + 1
        Write-Host "$fileSuffix is only in folder 1"
    }
}

$secondFolder = Get-ChildItem -Recurse $folder2 | Where-Object { -not $_.PsIsContainer }

$i = 0
$totalCount = $secondFolder.Count
$secondFolder | ForEach-Object {
    $i = $i + 1
    Write-Progress -Activity "Searching for files only on second folder" -status "Searching File  $i of $totalCount" -percentComplete ($i / $secondFolder.Count * 100)
    # Check if the file, from $folder2, exists with the same path under $folder1
    If (!(Test-Path($_.FullName.Replace($folder2, $folder1))))
    {
        $fileSuffix = $_.FullName.TrimStart($folder2)
        $failedCount = $failedCount + 1
        Write-Host "$fileSuffix is only in folder 2"
    }
}

Answer 3

您只需围绕已回答此问题的链接问题的正确答案进行循环，然后遍历目录树比较每个具有相同名称的文件。

/编辑：如果这确实是您的问题，那么它更适合SO，您似乎是定期贡献者。你问的是一个编程问题。我知道您这样做是为了系统管理员类型的目的，在这种情况下，我会告诉您使用 WinDiff 等专用工具。