Postgres 插入错误:架构公共权限被拒绝

Rud*_*uch 12 postgresql sql

在 Postgres 中,我在名为 的数据库中创建了下表testing

CREATE TABLE category_google_taxonomy (
    category_id integer references category ON UPDATE CASCADE ON DELETE CASCADE,
    google_taxonomy_id integer references google_taxonomy ON UPDATE CASCADE ON DELETE     CASCADE
);
Run Code Online (Sandbox Code Playgroud)

当我尝试填充表格时:

INSERT INTO category_google_taxonomy (category_id, google_taxonomy_id) VALUES
(1,7),
(2,12);
Run Code Online (Sandbox Code Playgroud)

我收到以下错误:

ERROR:  permission denied for schema public
LINE 1: SELECT 1 FROM ONLY "public"."category" x WHERE "category_id"...
                       ^
QUERY:  SELECT 1 FROM ONLY "public"."category" x WHERE "category_id" OPERATOR(pg_catalog.=) $1 FOR SHARE OF x
Run Code Online (Sandbox Code Playgroud)

我读了一点,最终ALL PRIVILEGES出于愤怒而同意,但它仍然不起作用:

testing=# GRANT ALL PRIVILEGES ON public.category TO testing;
GRANT

testing=# \dp category_google_taxonomy
                                   Access privileges
 Schema |           Name           | Type  |    Access privileges    | Column access privileges 
--------+--------------------------+-------+-------------------------+--------------------------
 public | category_google_taxonomy | table | testing=arwdDxt/testing | 
                                           : super=arwdDxt/testing 


testing=# \dp category
                           Access privileges
 Schema |   Name   | Type  |   Access privileges    | Column access privileges 
--------+----------+-------+------------------------+--------------------------
 public | category | table | testing=arwdDxt/super | category_id:
                                                :   testing=arwx/super
(1 row)
Run Code Online (Sandbox Code Playgroud)

根据@Daniel 的建议,我尝试了GRANT USAGE ON schema public TO super;,现在当我运行INSERT命令时,我得到:

ERROR:  permission denied for relation category
CONTEXT:  SQL statement "SELECT 1 FROM ONLY "public"."category" x WHERE "category_id" OPERATOR(pg_catalog.=) $1 FOR SHARE OF x"
Run Code Online (Sandbox Code Playgroud)

这是的相关部分\d

public | category                               | table    | super
public | category_google_taxonomy               | table    | testing
Run Code Online (Sandbox Code Playgroud)

Dan*_*ité 19

假设用户名是testing,你可能想要这样做:

GRANT ALL ON schema public TO testing;
Run Code Online (Sandbox Code Playgroud)

关于授予的注意事项ALL PRIVILEGES:您没有说明GRANT应用了此命令的内容。假设它是ON DATABASE...,它只是手段CONNECTCREATETEMP特权,任何关于公共架构或任何其他包含的对象,这就是为什么它“不工作”。

编辑:当这还不够时

如果外键引用的表不属于testing,则其所有者还需要具有USAGE对架构特权才能查找引用的表。

\dp(的结果\d肯定会告诉)结果并不明显,但如果categorysuper该用户拥有并且该用户对架构也没有特权,则需要为其分配:

GRANT USAGE ON schema public TO super;
Run Code Online (Sandbox Code Playgroud)

  • 我运行了“GRANT ALL ON schema”,但仍然遇到与以前相同的错误。“testing”是正确的用户。我添加了原来的 GRANT 命令,它位于表上,而不是整个数据库上。 (2认同)