小编Fer*_*H-G的帖子

我收到此错误：

当我尝试执行以下查询时出现：

with expensive_service as (
    select s1.*
    from service s1, service s2
    where s1.price > s2.price
)
select * 
from service except expensive_service;

我试图实现WITH ... AS（链接到 PostgreSQL 文档）。

此查询为我提供了所需的输出：

select * 
from service except ( 
    select s1.*
    from service s1, service s2
    where s1.price > s2.price
)

任何指导我错误所在的帮助将不胜感激！