将字母与数字字符串中的数字分开

Question

我有一个字母数字字符串作为输入，我想从中得到两个结果：

• 删除所有数字的字符串

  和

• 一个整数，它是输入字符串中所有数字的总和。

例如，对于这个输入：

GR35hc7vdH35

我想要以下输出：

| Col1.         |        Col2    |
----------------------------------
| GRhcvdH       |        23      |

怎么能做到这一点？

Answer 1

SQL Server 不支持替换多个字符的模式 - 所以通过它REPLACE可能需要 10 个操作。

考虑到这一点，一种方法是使用递归 CTE 顺序处理数字 0-9。

它进行替换，然后检查前后字符串的长度，以了解该数字有多少个字符以及需要添加到总数中的内容。

DECLARE @Input VARCHAR(8000) = 'GR35hc7vdH35';

WITH R(Level,Input,Accumulator,StringLength)
     AS (SELECT 0,
                Input,
                0,
                DATALENGTH(Input)
         FROM   (SELECT REPLACE(@Input, '0', '')) D(Input)
         UNION ALL
         SELECT NewLevel,
                NewInput,
                Accumulator + NewLevel * ( StringLength - NewStringLength ),
                NewStringLength
         FROM   R
                CROSS APPLY (SELECT Level + 1) C(NewLevel)
                CROSS APPLY (SELECT REPLACE(Input, NewLevel, '')) C2(NewInput)
                CROSS APPLY (SELECT DATALENGTH(NewInput)) C3(NewStringLength)
         WHERE  NewLevel <= 9)
SELECT Input       AS Col1,
       Accumulator AS Col2
FROM   R
WHERE  Level = 9;

或者您可以使用 CLR 和正则表达式（SQL Server 2012 兼容版本）。

DECLARE @Input VARCHAR(8000) = 'GR35hc7vdH35';

WITH R(Level,Input,Accumulator,StringLength)
     AS (SELECT 0,
                Input,
                0,
                DATALENGTH(Input)
         FROM   (SELECT REPLACE(@Input, '0', '')) D(Input)
         UNION ALL
         SELECT NewLevel,
                NewInput,
                Accumulator + NewLevel * ( StringLength - NewStringLength ),
                NewStringLength
         FROM   R
                CROSS APPLY (SELECT Level + 1) C(NewLevel)
                CROSS APPLY (SELECT REPLACE(Input, NewLevel, '')) C2(NewInput)
                CROSS APPLY (SELECT DATALENGTH(NewInput)) C3(NewStringLength)
         WHERE  NewLevel <= 9)
SELECT Input       AS Col1,
       Accumulator AS Col2
FROM   R
WHERE  Level = 9;

示例用法

SELECT Stripped,
       Total
FROM   [dbo].[ReplaceAndTotalise]('GR35hc7vdH35') 

Answer 2

请尝试以下操作：

CREATE FUNCTION dbo.AlphaNumericSplitter 
(
    @string varchar(8000)
)
RETURNS TABLE
AS
RETURN  (
    WITH    Alphanumeric (col1)
    AS      (
            -- Put out string into a cte table
            SELECT @string
            ),
            Nmbrs (n)
    AS      (
            -- Numbers so we can split the string
            SELECT  TOP(LEN(@string))
                    ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
            FROM    sys.all_objects AS o1
            CROSS
            JOIN    sys.all_objects AS o2
            ),
            y
    AS      (
            SELECT  N.n
                    a.col1,
                    N.x,
                    -- Get the numbers only
                    Numbers = TRY_CONVERT(int, N.x)
            FROM    Alphanumeric AS a
            CROSS 
            APPLY   (SELECT [x] = SUBSTRING(a.col1, n, 1), Nmbrs.n FROM Nmbrs) AS N
            )
    SELECT  z.Col1,
            Col2 = SUM(y.Numbers)
    FROM    y
    --  Get the letters only
    CROSS
    APPLY   (SELECT (SELECT x + '' FROM y WHERE Numbers IS NULL ORDER BY y.n FOR XML PATH(''))) AS z (Col1)
    GROUP   BY
            z.Col1);
GO

SELECT * FROM AlphaNumericSplitter('GR35hc7vdH35');

结果：