如何返回存储为日期和时间的两个日期时间之间的行？

Question

如何查看两个日期和时间之间的结果？

我目前的代码：

SELECT * 
FROM [DB].[dbo].[TABLE] 
WHERE [USER_ID] = '005'    
AND [DATE] BETWEEN '03-04-2016' AND '04-04-2016'
AND [TIME] >= '21:00:00'                   -- for date 03-04-2016
AND [TIME] <= '05:00:00'                   -- for date 04-04-2016

ORDER BY [DATE] ASC, [TIME] ASC

此代码不起作用，我不知道如何修复它

为什么这个请求不起作用？

Answer 1

任何行都不可能同时满足[TIME] >= '21:00:00'和 [TIME] <= '05:00:00'

SQL Server 不会读取您的源代码注释来知道应该有条件地应用时间。

您需要更改代码以便在边界日期上有条件地应用这些谓词（假设搜索日期为剩余谓词），因此时间元素仅与这些条件适用的日期相关。

SELECT *
FROM [DB].[dbo].[TABLE] 
WHERE [USER_ID] = '005'   
AND [DATE] BETWEEN '20160403' AND '20160404'
AND ([TIME] >= '21:00:00' OR [DATE] > '20160403')
AND ([TIME] <= '05:00:00' OR [DATE] < '20160404') ;

或等价物（虽然您需要检查执行计划以提高效率，但可能更多地自我记录）：

SELECT *
FROM [DB].[dbo].[TABLE] 
WHERE [USER_ID] = '005'   
AND ( [DATE] = '20160403' AND [TIME] >= '21:00:00'
  -- OR [DATE] > '20160403' AND [DATE] < '20160404'
   OR [DATE] = '20160404' AND [TIME] <= '05:00:00'
    ) ;