我有一个像这样的 MySQL 表:
User_Id course_name course_location course_id
1 course name 1 location 1 1
1 course name 2 location 2 2
1 course name 3 location 1 3
2 course name 2 location 1 2
2 course name 4 location 4 4
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我怎样才能得到这样的数据:
User_id course 1 course2 course3 course4
1 yes-location1 yes-location2 yes-location1 NULL
2 NULL yes-location1 NULL yes-location4
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您必须使用GROUP BYwithMAX聚合透视数据并用于CASE过滤User_id。
SELECT User_id
, MAX(
CASE WHEN course_id = 1 THEN course_location END
) as Course_1
, MAX(CASE WHEN course_id = 2 THEN course_location END) as Course_2
, MAX(CASE WHEN course_id = 3 THEN course_location END) as Course_3
, MAX(CASE WHEN course_id = 4 THEN course_location END) as Course_4
FROM data
GROUP BY User_id;
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SQL Fiddle 中的示例查询。
您可以替换course_location的CONCAT('YES-', course_location)是全球领先的YES确实是必要的。
User_Id | Course_1 | Course_2 | Course_3 | Course_4
1 | location 1 | location 2 | location 1 | (null)
2 | (null) | location 1 | (null) | location 4
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