我想在一行而不是多行中显示每个人的联系信息和他们的佣金。
ID COMMISSION DATE
N12545233 774 4/1/15
N12545233 361 5/1/14
N12545233 685 6/1/15
N14521746 3384 10/1/14
N14521746 1188 11/1/14
N14521746 1256 12/1/14
N15981070 1188 1/1/15
N15981070 616 2/1/15
N15981070 936 3/1/15
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ID LASTNAME FIRSTNAME STREET CITY STATE ZIP
N12545233 Jones Mark 123 Main St Brooklyn NY 11377
N14521746 Greene Phil 345 Broadway Queens NY 11237
N15981070 Stahl Barbara 567 Lexington New York NY 10018
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ID LASTNAME FIRSTNAME STREET CITY STATE ZIP COMMISSION DATE COMMISSION DATE COMMISSION DATE
N12545233 Jones Mark 123 Main St Brooklyn NY 11377 774 4/1/15 361 5/1/14 685 6/1/15
N14521746 Greene Phil 345 Broadway Queens NY 11237 3384 10/1/14 1188 11/1/14 1256 12/1/14
N15981070 Stahl Barbara 567 Lexington New York NY 10018 1188 1/1/15 616 2/1/15 936 3/1/15
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如果您在 MySQL 上运行:
SELECT
c.ID,
ss.LASTNAME,
ss.FIRSTNAME,
ss.STREET,
ss.CITY,
ss.STATE,
ss.ZIP,
GROUP_CONCAT(c.COMMISSION ORDER BY c.DATE SEPARATOR '\n') AS COMMISSION,
GROUP_CONCAT(c.DATE ORDER BY c.DATE SEPARATOR '\n') AS DATE
FROM db1.Sales_Staff AS ss
JOIN db1.Commission AS c ON (c.ID=ss.ID)
ORDER BY ss.LASTNAME ASC,ss.FIRSTNAME ASC;
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