帮助将 SQL 查询转换为 XML 输出

Question

我有以下查询：

SELECT    
    [ID] AS [NewID]
    , (
       CASE WHEN LEN([MiddleName]) > 0 THEN
          [LastName] + ', ' + [FirstName] + ' ' + LEFT([MiddleName],1) + '.'
       ELSE
          [LastName] + ', ' + [FirstName]
       END
    ) AS [Name]
    , [Title] AS [ProfTitle]
    , CONVERT(CHAR(10),[DepartureDate],111) AS [BorDepart]
    , [LocationOfficeNumber] AS [OfficePhone]
    , [Location]
    , [LocationSection] AS [Sec]
    , [PracticeGroup] AS [PracticeTL]
    , [Email]         
FROM [dbo].[Borrowers]

有了这个，我想知道如何编写一个转换为这个输出的 FOR XML 查询：

<sydney>
    <import>
        <template id="Borrower" name="Borrowers">
            <record searchfield="NewID" searchvalue="NewID">
                <field id="NewID">
                    <![CDATA[NEWID]]>
                </field>                
                <field id="Name">
                    <![CDATA[NAME]]>
                </field>                
                <field id="ProfTitle">
                    <![CDATA[Professional Title]]>
                </field>                
                <field id="BorDepart">
                    <![CDATA[YYYY/MM/DD]]>
                </field>                
                <field id="OfficePhone">
                    <![CDATA[office phone]]>
                </field>
                <link id="Location" linkfield="Code">
                    <![CDATA[011]]>
                </link>
                <link id="Sec" linkfield="Term">
                    <![CDATA[SECTION]]>
                </link>
                <link id="PracticeTL" linkfield="Term">
                    <![CDATA[SUBSECTION]]>
                </link>
                <field id="Email">
                    <![CDATA[email]]>
                </field>
            </record>
        </template>
    </import>
</sydney>

我已经尝试了 FOR XML PATH 和 FOR XML EXPLICIT 的各种组合，但找不到任何答案。我最接近的是这个：

SELECT (
    SELECT 
       'Borrower' AS '@id'
       , 'Borrowers' AS '@name'
       , (
          SELECT
             'NewID' AS '@searchfield'
             , 'NewID' AS '@searchvalue'
             , [ID] AS 'NewID' --AS [Field!1!CDATA]

             , (
                CASE WHEN LEN([MiddleName]) > 0 THEN
                    [LastName] + ', ' + [FirstName] + ' ' + LEFT([MiddleName],1) + '.'
                ELSE
                    [LastName] + ', ' + [FirstName]
                END
             ) AS [Name]
             , [Title] AS [ProfTitle]
             , CONVERT(CHAR(10),[DepartureDate],111) AS [BorDepart]
             , [LocationOfficeNumber] AS [OfficePhone]
             , [Location]
             , [LocationSection] AS [Sec]
             , [PracticeGroup] AS [PracticeTL]
             , [Email]        
          FROM [dbo].[Borrowers]
          FOR XML PATH('record'), TYPE
       )
    FOR XML PATH('template'), TYPE
) AS 'import'
FOR XML PATH('sydney'), TYPE

欢迎任何帮助，因为我已经坚持了一个星期并且找不到任何东西。

PS：这是 Borrowers 表的架构：

干杯，

阿尔瓦罗·科斯塔

Answer 1

这是一个工作FOR XML EXPLICIT示例。它们有点难以编码，但我倾向于逐节构建它们，因此它们还不错：

USE tempdb
GO

SET NOCOUNT ON
GO

IF OBJECT_ID('dbo.Borrowers') IS NOT NULL DROP TABLE dbo.Borrowers
CREATE TABLE dbo.Borrowers
(
    ID                      INT IDENTITY PRIMARY KEY,
    FirstName               VARCHAR(30),
    MiddleName              VARCHAR(30),
    LastName                VARCHAR(30),
    Title                   VARCHAR(30),
    DepartureDate           DATE,
    LocationOfficeNumber    VARCHAR(30),
    Location                VARCHAR(30),
    LocationSection         VARCHAR(30),
    PracticeGroup           VARCHAR(30),
    Email                   VARCHAR(30)
)
GO

INSERT INTO dbo.Borrowers( FirstName, MiddleName, LastName, Title, DepartureDate, LocationOfficeNumber, Location, LocationSection, PracticeGroup, Email )
VALUES 
    ( 'Alvaro', 'X', 'Costa', 'Mr', GETDATE(), '000-000', 'Location 1', 'Location Section 2', 'Practice Group 3', 'alvaro@nospam.com' ),
    ( 'w', '', 'Bob', 'Mr', GETDATE(), '000-007', 'Location 2', 'Location Section 3', 'Practice Group 4', 'wBob@nospam.com' )
GO


SELECT
      1             AS Tag
    , NULL          AS Parent
    , NULL          AS [import!1]
    , NULL          AS [template!2!id]
    , NULL          AS [template!2!name]
    , NULL          AS [record!3!searchfield]
    , NULL          AS [record!3!searchvalue]
    , NULL          AS [record!3!sort!HIDE]

    , NULL          AS [field!4!id]         -- NewID
    , NULL          AS [field!4!!CDATA]

    , NULL          AS [field!4!id]         -- Name
    , NULL          AS [field!4!!CDATA]

    , NULL          AS [field!4!id]         -- ProfTitle
    , NULL          AS [field!4!!CDATA]

    , NULL          AS [field!4!id]         -- BorDepart
    , NULL          AS [field!4!!CDATA]

    , NULL          AS [field!4!id]         -- OfficePhone
    , NULL          AS [field!4!!CDATA]

    , NULL          AS [link!5!id]          -- Location
    , NULL          AS [link!5!linkfield]
    , NULL          AS [link!5!!CDATA]

    , NULL          AS [link!5!id]          -- Sec
    , NULL          AS [link!5!linkfield]
    , NULL          AS [link!5!!CDATA]

    , NULL          AS [link!5!id]          -- PracticeTL
    , NULL          AS [link!5!linkfield]
    , NULL          AS [link!5!!CDATA]

    , NULL          AS [field!4!id]         -- Email
    , NULL          AS [field!4!!CDATA]

UNION ALL

SELECT
      2
    , 1
    , NULL
    , 'Borrower'
    , 'Borrowers'
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

UNION ALL

SELECT
      3
    , 2
    , NULL
    , NULL
    , NULL
    , 'NewID'
    , 'NewID'
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      4
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , 'NewID'
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      4
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , 'Name'
    , LastName
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      4
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , 'ProfTitle'
    , Title
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      4
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , 'BorDepart'
    , CONVERT( CHAR(10), DepartureDate, 111 )
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      4
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , 'OfficePhone'
    , LocationOfficeNumber
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      5
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , 'Location'
    , 'Code'
    , Location
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      5
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , 'Sec'
    , 'Term'
    , LocationSection
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      5
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , 'PracticeTL'
    , 'Term'
    , PracticeGroup
    , NULL
    , NULL

FROM dbo.Borrowers

UNION ALL

SELECT
      4
    , 3
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , ID
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , NULL
    , 'Email'
    , Email

FROM dbo.Borrowers
ORDER BY [record!3!sort!HIDE]
FOR XML EXPLICIT, ROOT('sydney')

HTH

Answer 2

如果你这样做，'NewID' as [field/@id]你会得到一个field带有id属性的元素。在下一行中，您添加B.ID as [field]的值ID作为field您之前在该行上创建的节点的节点值。

<field id="NewID">1</field>

之后，您需要一个新field节点并创建该节点，您可以使用一个没有名称的节点null as [*]作为field节点之间的分隔符。

这是用于您要创建的每个字段节点的模式。

'NewID' as [field/@id],
B.ID as [field],
null as [*],

您的查询将如下所示。

select 'Borrower' as [template/@id],
       'Borrowers' as [template/@name],
       (
       select 'NewID' as [@searchfield],
              'NewID' as [@searchvalue],

              'NewID' as [field/@id],
              B.ID as [field],
              null as [*],

              'Name' as [field/@id],
              case when len(B.MiddleName) > 0
                then B.LastName + ', ' + B.FirstName + ' ' + left(B.MiddleName, 1) + '.'
                else B.LastName + ', ' + B.FirstName
              end as [field],
              null as [*],

              'ProfTitle' as [field/@id],
              B.Title as [field]

      from dbo.Borrowers as B
      for xml path('record'), type
      ) as 'template'
for xml path('import'), root('sydney')

结果

<sydney>
  <import>
    <template id="Borrower" name="Borrowers">
      <record searchfield="NewID" searchvalue="NewID">
        <field id="NewID">1</field>
        <field id="Name">Last, First M.</field>
        <field id="ProfTitle">Tit</field>
      </record>
    </template>
  </import>
</sydney>