对于大学课程,我被赋予了以下任务
假设我们有employee一张像(first_name, last_name, salary, hire_date, ...). 有规定规定,每位员工在入职后每年都必须与公司续签合同。显示每位员工下一次续约前还有多少个月。
这是我的尝试:
select (abs(months_between(sysdate,hire_date)/12 -
round((months_between(sysdate,e.hire_date))/12)))
from employees e
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如果您的员工表很大,有更有效的方法可以做到这一点,但这是我觉得最容易理解的方式:)
试验台:
create table employee( employee_id integer primary key,
name varchar(100) not null,
hire_date date not null );
insert into employee(employee_id, name, hire_date)
values(1, 'Alice', to_date('20090909', 'YYYYMMDD'));
insert into employee(employee_id, name, hire_date)
values(2, 'Bob', to_date('20101010', 'YYYYMMDD'));
insert into employee(employee_id, name, hire_date)
values(3, 'Chris', to_date('20111111', 'YYYYMMDD'));
insert into employee(employee_id, name, hire_date)
values(4, 'David', to_date('20101231', 'YYYYMMDD'));
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询问:
with w as ( select e.*, ( select max(add_months(hire_date, 12*level))
from dual
connect by add_months(hire_date, 12*(level-1))<sysdate )
as next_anniversary
from employee e )
select w.*, round(months_between(next_anniversary, sysdate)) as months_from_now from w;
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结果:
EMPLOYEE_ID NAME HIRE_DATE NEXT_ANNIVERSARY MONTHS_FROM_NOW
---------------------- ---------- ------------------------- ------------------------- ----------------------
1 Alice 09-SEP-09 00.00.00 09-SEP-12 00.00.00 10
2 Bob 10-OCT-10 00.00.00 10-OCT-12 00.00.00 11
3 Chris 11-NOV-11 00.00.00 11-NOV-12 00.00.00 12
4 David 31-DEC-10 00.00.00 31-DEC-11 00.00.00 1
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你可能喜欢floor或ceil到round。
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