由于未正确编写查询,我的 mysql 服务器出现问题。我没有使用索引,因为我不知道如何在具有SELECT COUNT(*) AS b ... ORDER BY b
.
看起来不可能,所以如果确实不可能,我如何重新管理我的查询?
SELECT COUNT(downloaded.id) AS downloaded_count
, downloaded.file_name
,uploaded.*
FROM `downloaded` JOIN uploaded
ON downloaded.file_name = uploaded.file_name
WHERE downloaded.completed = 1
AND uploaded.active = 1
AND uploaded.nsfw = 0
AND downloaded.datetime > DATE_SUB(NOW(), INTERVAL 7 DAY)
GROUP BY downloaded.file_name
ORDER BY downloaded_count DESC LIMIT 30;
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解释
+----+-------------+------------+------+---------------+-----------+---------+--------------------------+------+----------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+------------+------+---------------+-----------+---------+--------------------------+------+----------------------------------------------+
| 1 | SIMPLE | uploaded | ALL | file_name_up | NULL | NULL | NULL | 3139 | Using where; Using temporary; Using filesort |
| 1 | SIMPLE | downloaded | ref | file_name | file_name | 767 | piqik.uploaded.file_name | 8 | Using where |
+----+-------------+------------+------+---------------+-----------+---------+--------------------------+------+----------------------------------------------+
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更新:
与 ORDER BY;
Showing rows 0 - 29 ( 30 total, Query took 0.1639 sec)
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没有 ORDER BY;
Showing rows 0 - 29 ( 30 total, Query took 0.0064 sec)
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更新 #2:
表:已上传(总计 720.5 KiB)
CREATE TABLE IF NOT EXISTS `uploaded` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`sid` int(1) NOT NULL,
`file_name` varchar(255) NOT NULL,
`file_size` varchar(255) NOT NULL,
`file_ext` varchar(255) NOT NULL,
`file_name_keyword` varchar(255) NOT NULL,
`access_key` varchar(40) NOT NULL,
`upload_datetime` datetime NOT NULL,
`last_download` datetime NOT NULL,
`file_password` varchar(255) NOT NULL DEFAULT '',
`nsfw` int(1) NOT NULL,
`votes` int(11) NOT NULL,
`downloads` int(11) NOT NULL,
`video_thumbnail` int(1) NOT NULL DEFAULT '0',
`video_duration` varchar(255) NOT NULL DEFAULT '',
`video_resolution` varchar(11) NOT NULL,
`video_additional` varchar(255) NOT NULL DEFAULT '',
`active` int(1) NOT NULL DEFAULT '1',
PRIMARY KEY (`id`),
FULLTEXT KEY `file_name_keyword` (`file_name_keyword`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=3328 ;
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表:已下载(总计 5,152.0 KiB)
CREATE TABLE IF NOT EXISTS `downloaded` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`file_name` varchar(255) NOT NULL,
`completed` int(1) NOT NULL,
`client_ip_addr` varchar(40) NOT NULL,
`client_access_key` varchar(40) NOT NULL,
`datetime` datetime NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=31475 ;
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您可以通过多种方式提高查询效率。
首先,索引表。好的,这样做并不容易。并且应该考虑与您在数据库中运行的所有查询相关的任何索引。让我们假设这是唯一的查询或者它是最关键的查询。
我们将把这个任务分解成涉及的 2 个表。第一个表 ,uploaded
出现 - 除了连接 - 仅在选择列表(其所有列)和 2 个WHERE
条件中出现:
AND uploaded.active = 1
AND uploaded.nsfw = 0
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两个简单的相等条件,所以直接的想法是在这两列上建立索引,或者更好地包括连接列(这是一个技术问题,因为该表使用的是 MyISAM 引擎): (active, nsfw, file_name)
ALTER TABLE uploaded
ADD INDEX active_nsfw_fname_IX
(active, nsfw, filename) ;
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桌边。这个比较复杂。它的列不会出现在选择列表中(只有聚合结果,计数),但它们用于WHERE
,GROUP BY
子句和ORDER BY / LIMIT
. 更复杂的是,条件之一是范围条件 ( >
) 而不是相等:
WHERE downloaded.completed = 1
AND downloaded.datetime > DATE_SUB(NOW(), INTERVAL 7 DAY)
GROUP BY downloaded.file_name
ORDER BY downloaded_count DESC LIMIT 30
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如果两者都是相等的,我会盲目地添加一个索引 on(completed, datetime, file_name)
但在这种情况下,我会首先尝试一个索引 on (completed, file_name, datetime)
,即首先来自相等检查的列,然后是分组中的列,最后是另一个。
ALTER TABLE downloaded
ADD INDEX comp_fname_dt_IX
(completed, file_name, datetime) ;
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并且LIMIT
首先在派生表中执行此操作然后连接其他表的查询中,通常可能的另一个改进。我们不能在这里完全做到这一点,但我们可以尝试将其放入派生表中。
请注意,从uploaded
表中仅active_nsfw_fname_IX
使用索引中的列并且对于该downloaded
表,comp_fname_dt_IX
索引的列与查询(逻辑上)执行的顺序对齐(WHERE - GROUP BY - SELECT
):
( SELECT COUNT(CASE WHEN d.datetime > DATE_SUB(NOW(), INTERVAL 7 DAY) THEN 1 END)
AS downloaded_count
, d.file_name
FROM downloaded AS d JOIN uploaded AS u
ON d.file_name = u.file_name
WHERE d.completed = 1
AND u.active = 1
AND u.nsfw = 0
GROUP BY d.file_name
ORDER BY downloaded_count DESC LIMIT 30
)
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SELECT dc.downloaded_count
, dc.file_name -- you can remove this column from the results
, up.* -- as uploaded has a file_name column
FROM
( SELECT COUNT(CASE WHEN d.datetime > DATE_SUB(NOW(), INTERVAL 7 DAY) THEN 1 END)
AS downloaded_count
, d.file_name
FROM downloaded AS d JOIN uploaded AS u
ON d.file_name = u.file_name
WHERE d.completed = 1
AND u.active = 1
AND u.nsfw = 0
GROUP BY d.file_name
ORDER BY downloaded_count DESC LIMIT 30
) AS dc
JOIN uploaded AS up
ON dc.file_name = up.file_name
ORDER BY downloaded_count DESC ; -- no need for LIMIT here
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测试时间!我建议您添加这 2 个索引,然后对查询进行计时,包括原始索引和上面的索引。
并且要回答您的问题,不能对聚合列进行索引。MySQL 既没有计算列也没有物化视图,这在这种情况下是需要的(只有 MariaDB 实现了持久的计算列,但这对您在这个查询中没有帮助。)
因此,唯一的方法是尝试通过索引和重写查询来尽可能地减少将要排序的行数 - 这就是我在上面基本上试图完成的。
您仍然会在 中看到 a "filesort"
,EXPLAIN
但对 100 行和 10k 行进行排序是完全不同的(在性能方面)。