PostgreSQL:使用其他表中的模式和表名?

Cha*_*hau 8 postgresql dynamic-sql

考虑这样一种情况,我的所有模式名称都在一个表中,而我的所有表名称都在另一个表中。

是否可以执行以下操作(伪代码)?

SELECT value FROM (SELECT schema_name FROM schemas).(SELECT table_name FROM tables)
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或者我必须将查询分解为三个 SELECT 吗?

Erw*_*ter 8

杰克已经示范了要走的路。不过,我觉得还有改进的余地。

测试设置:

-- meta tables for schema and table name    
CREATE TABLE schma(schma_id int, schma text);
INSERT INTO  schma VALUES (1, 'x');

CREATE TABLE tbl(tbl_id int, tbl text);
INSERT INTO  tbl VALUES (1, 't1'), (2, 't2');

-- dummy tables to be used in example query:
CREATE TABLE t1(id int);
INSERT INTO  t1 VALUES (1),(2);

CREATE TABLE t2(foo text);
INSERT INTO  t2 VALUES ('some text'), ('some more text');
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format()2017年更新功能;2021 年格式:

CREATE OR REPLACE FUNCTION f_dynaquery(_schma_id int
                                     , _tbl_id int
                                     , _col text
                                     , _type anyelement)
  RETURNS TABLE(col anyelement)
  LANGUAGE plpgsql AS
$func$
BEGIN
   RETURN QUERY EXECUTE format(
      'SELECT %I FROM %I.%I'
    , _col
    , (SELECT schma FROM schma WHERE schma_id = _schma_id)
    , (SELECT tbl   FROM tbl   WHERE tbl_id   = _tbl_id)
   );
END
$func$;

COMMENT ON FUNCTION f_dynaquery(int, int, text, anyelement)
IS 'Query any column from a dynamically assembled tablename.
$1 .. id of schema
$2 .. id of table
$3 .. name of column
$4 .. type of column (only data type matters, not the value)';
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db<>在这里摆弄

称呼:

SELECT col FROM f_dynaquery(1, 1, 'id', NULL::int);
  col
-----
   1
   2

SELECT col FROM f_dynaquery(1, 2, 'foo', NULL::text);
  col
----------------
 some text
 some more text
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该函数可以返回任何类型的任何列
阅读有关多态类型声明函数参数的手册。

使用format()防御SQL注入。看:

根据要求通过查询检索表名。

命名返回的列,以便更容易引用。

原答案:

CREATE OR REPLACE FUNCTION f_dynaquery_old(int, int, _col text, _type anyelement, OUT col anyelement)
  RETURNS SETOF anyelement
  LANGUAGE plpgsql AS
$func$
BEGIN
   RETURN QUERY EXECUTE '
   SELECT ' || quote_ident(_col) || '
   FROM   ' || (
       (SELECT schma FROM schma WHERE schma_id = $1) || '.' ||
       (SELECT tbl   FROM tbl   WHERE tbl_id   = $2))::regclass;
END
$func$;
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通过使用quote_ident()强制转换为regclass.


Jac*_*las 7

您需要动态 SQL - 也许是这样的:

create role stack;
create schema authorization stack;
set role stack;

create or replace function f(p_schema in text, p_table in text)
                           returns setof integer language plpgsql immutable as $$
begin
  return query execute 'select value from '||p_schema||'.'||p_table;
end;$$;

create table t1(value integer);
insert into t1(value) values (1);
insert into t1(value) values (2);

create table t2(value integer);
insert into t2(value) values (1);

create table schemas(schema_name text);
insert into schemas(schema_name) values ('stack');

create table tables(table_name text);
insert into tables(table_name) values ('t1');
insert into tables(table_name) values ('t2');
insert into tables(table_name) values ('t1');
insert into tables(table_name) values ('t2');

select f(schema_name, table_name) from schemas cross join tables;
 f
---
 1
 2
 1
(3 rows)
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正如问题所暗示的那样,我假设每个表都存在于每个模式中