不知道还有什么办法可以解决这个问题。我有一个表,它有一个开始和一个停止列,我想返回它通过开始和停止连接的结果,我想清楚地区分两者。现在这两个查询分别快速运行:
SELECT
UNIX_TIMESTAMP(CONVERT_TZ(start_dev, '+00:00', GetCarrierTimezone(a0.carrier_id))) AS alertStart,
NULL AS alertStop,
c0.name AS carrier_name,
carrier_image,
l0.Latitude,
l0.Longitude
FROM
carriers AS c0
INNER JOIN start_stop AS a0 ON a0.carrier_id = c0.id
INNER JOIN pcoarg AS l0 ON a0.startLogId = l0.id
WHERE
FIND_IN_SET(a0.carrier_id, '89467,1,64578,222625,45013') > 0
AND
start_dev > '2013-03-11 11:46:48'
AND
start_dev = (SELECT MIN(start_dev) FROM start_stop AS a1 WHERE a0.carrier_id = a1.carrier_id AND DATE(a1.start_dev) = DATE(a0.start_dev))
AND IsNotificationInSchedule(22, start_dev) > 0
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所以这个需要 0.063。但是,如果我将它组合在一个 UNION 中(它是 UNION ALL 还是 DISTINCT 或 WHATEVER 都没有关系),它只需要大约 0.400 秒。
SELECT * FROM
(
(
SELECT
UNIX_TIMESTAMP(CONVERT_TZ(start_dev, '+00:00', GetCarrierTimezone(a0.carrier_id))) AS alertStart,
NULL AS alertStop,
c0.name AS carrier_name,
carrier_image,
l0.Latitude,
l0.Longitude
FROM
carriers AS c0
INNER JOIN start_stop AS a0 ON a0.carrier_id = c0.id
INNER JOIN pcoarg AS l0 ON a0.startLogId = l0.id
WHERE
FIND_IN_SET(a0.carrier_id, '89467,1,64578,222625,45013') > 0
AND
start_dev > '2013-03-11 11:46:48'
AND
start_dev = (SELECT MIN(start_dev) FROM start_stop AS a1 WHERE a0.carrier_id = a1.carrier_id AND DATE(a1.start_dev) = DATE(a0.start_dev))
AND IsNotificationInSchedule(22, start_dev) > 0
) UNION ALL (
SELECT
NULL AS alertStart,
UNIX_TIMESTAMP(CONVERT_TZ(stop_dev, '+00:00', GetCarrierTimezone(a0.carrier_id))) AS alertStop,
c0.name AS carrier_name,
carrier_image,
l0.Latitude,
l0.Longitude
FROM
start_stop AS a0
INNER JOIN carriers AS c0 ON a0.carrier_id = c0.id
INNER JOIN pcoarg AS l0 ON a0.stopLogId = l0.id
WHERE
FIND_IN_SET(a0.carrier_id, '89467,1,64578,222625,45013') > 0
AND
stop_dev > '2013-03-11 11:46:48'
AND
stop_dev = (SELECT MAX(stop_dev) FROM start_stop AS a1 WHERE a0.carrier_id = a1.carrier_id AND DATE(a1.stop_dev) = DATE(a0.stop_dev))
AND IsNotificationInSchedule(22, start_dev) > 0
)
) AS startStops
ORDER BY IF(alertStart IS NULL, alertStop, alertStart)
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这是单个查询的解释:
1 PRIMARY c0 ALL PRIMARY 17 Using where
1 PRIMARY a0 ref PRIMARY,startstop_carriers_stopdev_idx,georefidx,startstop_carriers_startdev_idx startstop_carriers_stopdev_idx 4 test_backoffice.c0.id 72 Using where
1 PRIMARY l0 ref id ASC id ASC 4 test_backoffice.a0.startLogId 1 Using where
2 DEPENDENT SUBQUERY a1 ref PRIMARY,startstop_carriers_stopdev_idx,georefidx,startstop_carriers_startdev_idx startstop_carriers_stopdev_idx 4 test_backoffice.a0.carrier_id 72 Using where; Using index
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这是 JOIN 的解释:
1 PRIMARY <derived2> system 0 const row not found
2 DERIVED c0 ALL PRIMARY 17 Using where
2 DERIVED a0 ref PRIMARY,startstop_carriers_stopdev_idx,georefidx,startstop_carriers_startdev_idx startstop_carriers_stopdev_idx 4 test_backoffice.c0.id 72 Using where
2 DERIVED l0 ref id ASC id ASC 4 test_backoffice.a0.startLogId 1 Using where
3 DEPENDENT SUBQUERY a1 ref PRIMARY,startstop_carriers_stopdev_idx,georefidx,startstop_carriers_startdev_idx startstop_carriers_stopdev_idx 4 test_backoffice.a0.carrier_id 72 Using where; Using index
4 UNION c0 ALL PRIMARY 17 Using where
4 UNION a0 ref PRIMARY,startstop_carriers_stopdev_idx,georefidx,startstop_carriers_startdev_idx startstop_carriers_stopdev_idx 4 test_backoffice.c0.id 72 Using where
4 UNION l0 ref id ASC id ASC 4 test_backoffice.a0.stopLogId 1 Using where
5 DEPENDENT SUBQUERY a1 ref PRIMARY,startstop_carriers_stopdev_idx,georefidx,startstop_carriers_startdev_idx startstop_carriers_stopdev_idx 4 test_backoffice.a0.carrier_id 72 Using where; Using index
UNION RESULT <union2,4> ALL
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对此的帮助将不胜感激。:)
编辑:
我得到不一致的结果。例如,如果我删除 convert_tz 并尝试在联合之外获取时区,我会得到非常快的结果,但是如果我重命名结果,它会自动归结为相同的性能不佳的查询:
SELECT
*,
GetCarrierTimezone(carrier_id) timezone
FROM
(
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这需要 0.374 秒
SELECT
*,
GetCarrierTimezone(carrier_id)
FROM
(
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而这需要 0.078(主要是从数据库到我的机器的延迟)。
小智 0
在一个非常非常相似的情况下,我从mysql的进程列表中注意到“复制到临时表”的非常糟糕的行为(复制什么?我不知道)。我认为 mysql 尝试了一种“最佳方法”来进行查询,但在本例中失败了,因此使用代码来“合并”2 个查询结果效果很好。
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