如何在单列中计算工作时间?

M. *_* S. 2 sql-server datetime

我想计算从包含单个日期/时间字段的数据行工作所花费的时间。

给定日期的第一次出现可以被视为开始时间,下一次出现是结束时间,在任何给定日期来回交替。因此,如果我从上午 9:00 开始并在下午 12:00 吃午饭,在中午 12:30 吃完午饭返回,然后在下午 5:00 离开,我的数据将如下所示:

2013-03-07 09:00:00
2013-03-07 12:00:00
2013-03-07 12:30:00
2013-03-07 17:00:00
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这是另一个示例(在我的语言环境中,我们.用作日期分隔符):

22. 2. 2013 9:09:00
22. 2. 2013 13:28:09
25. 2. 2013 9:43:16
25. 2. 2013 15:15:19
25. 2. 2013 19:30:00
25. 2. 2013 21:30:00
26. 2. 2013 8:27:54
26. 2. 2013 16:31:51
27. 2. 2013 8:52:59
27. 2. 2013 15:08:35
28. 2. 2013 8:37:54
28. 2. 2013 16:37:08
28. 2. 2013 18:30:00
28. 2. 2013 20:30:00
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我想知道任何一天的工作总时间,并且还希望能够统计花费的时间,例如,任何给定的一周或一个月。

Aar*_*and 9

DECLARE @d TABLE(dt DATETIME);

INSERT @d VALUES
('2013-02-22 09:09:00'),
('2013-02-22 13:28:09'),
('2013-02-25 09:43:16'),
('2013-02-25 15:15:19'),
('2013-02-25 19:30:00'),
('2013-02-25 21:30:00'),
('2013-02-26 08:27:54'),
('2013-02-26 16:31:51'),
('2013-02-27 08:52:59'),
('2013-02-27 15:08:35'),
('2013-02-28 08:37:54'),
('2013-02-28 16:37:08'),
('2013-02-28 18:30:00'),
('2013-02-28 20:30:00');

;WITH x AS
(
  SELECT 
   e = dt,
   r = ROW_NUMBER() OVER (ORDER BY dt),
   p = LAG(dt, 1) OVER (ORDER BY dt),
   m = DATEDIFF(MINUTE, LAG(dt, 1) OVER (ORDER BY dt), dt)
 FROM @d
)
SELECT 
  start = p, 
  [end] = e, 
  [minutes_elapsed] = m, 
  [time] = CONVERT(TIME(0), DATEADD(MINUTE, m, 0))
 FROM x
 WHERE r % 2 = 0
 ORDER BY e;
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如果您需要在旧版本 (2005 -> 2008 R2) 上执行此操作:

;WITH cte1 AS
(
  SELECT 
   e = dt,
   r = ROW_NUMBER() OVER (ORDER BY dt)
  FROM @d
),
cte2 AS
(
  SELECT 
    x.r,
    [start] = x.e, 
    [end] = y.e, 
    m = DATEDIFF(MINUTE, x.e, y.e)
  FROM cte1 AS x INNER JOIN cte1 AS y
  ON x.r = y.r - 1
  WHERE y.r % 2 = 0
)
SELECT
  [start],
  [end],
  minutes_elapsed = m,
  [time] = CONVERT(CHAR(8), DATEADD(MINUTE, m, 0), 108)
 FROM cte2
 ORDER BY [start];
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记录时间/超时的建议模式非常简单:

CREATE TABLE dbo.Shifts
(
  EmployeeID INT NOT NULL, -- probably Foreign Key, right?
  ClockIn DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
  ClockOut DATETIME NULL
);
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现在您的查询是:

SELECT 
  EmployeeID, 
  ClockIn, 
  ClockOut, 
  ShiftLength = CONVERT(TIME(0), DATEADD(MINUTE, 
    DATEDIFF(MINUTE, ClockIn,  
      COALESCE(ClockOut, CURRENT_TIMESTAMP) -- to capture shift in progress
    ), 0))
FROM dbo.Shifts
WHERE ...
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  • 没问题。请注意,如果您在一对中丢失了一行,那么一切都会变得一团糟……您确实应该将开始时间和结束时间存储在单独的列中。以这种方式处理丢失的数据要容易得多(而且这个查询也会简单得多)。 (3认同)