M. *_* S. 2 sql-server datetime
我想计算从包含单个日期/时间字段的数据行工作所花费的时间。
给定日期的第一次出现可以被视为开始时间,下一次出现是结束时间,在任何给定日期来回交替。因此,如果我从上午 9:00 开始并在下午 12:00 吃午饭,在中午 12:30 吃完午饭返回,然后在下午 5:00 离开,我的数据将如下所示:
2013-03-07 09:00:00
2013-03-07 12:00:00
2013-03-07 12:30:00
2013-03-07 17:00:00
Run Code Online (Sandbox Code Playgroud)
这是另一个示例(在我的语言环境中,我们.
用作日期分隔符):
22. 2. 2013 9:09:00
22. 2. 2013 13:28:09
25. 2. 2013 9:43:16
25. 2. 2013 15:15:19
25. 2. 2013 19:30:00
25. 2. 2013 21:30:00
26. 2. 2013 8:27:54
26. 2. 2013 16:31:51
27. 2. 2013 8:52:59
27. 2. 2013 15:08:35
28. 2. 2013 8:37:54
28. 2. 2013 16:37:08
28. 2. 2013 18:30:00
28. 2. 2013 20:30:00
Run Code Online (Sandbox Code Playgroud)
我想知道任何一天的工作总时间,并且还希望能够统计花费的时间,例如,任何给定的一周或一个月。
DECLARE @d TABLE(dt DATETIME);
INSERT @d VALUES
('2013-02-22 09:09:00'),
('2013-02-22 13:28:09'),
('2013-02-25 09:43:16'),
('2013-02-25 15:15:19'),
('2013-02-25 19:30:00'),
('2013-02-25 21:30:00'),
('2013-02-26 08:27:54'),
('2013-02-26 16:31:51'),
('2013-02-27 08:52:59'),
('2013-02-27 15:08:35'),
('2013-02-28 08:37:54'),
('2013-02-28 16:37:08'),
('2013-02-28 18:30:00'),
('2013-02-28 20:30:00');
;WITH x AS
(
SELECT
e = dt,
r = ROW_NUMBER() OVER (ORDER BY dt),
p = LAG(dt, 1) OVER (ORDER BY dt),
m = DATEDIFF(MINUTE, LAG(dt, 1) OVER (ORDER BY dt), dt)
FROM @d
)
SELECT
start = p,
[end] = e,
[minutes_elapsed] = m,
[time] = CONVERT(TIME(0), DATEADD(MINUTE, m, 0))
FROM x
WHERE r % 2 = 0
ORDER BY e;
Run Code Online (Sandbox Code Playgroud)
如果您需要在旧版本 (2005 -> 2008 R2) 上执行此操作:
;WITH cte1 AS
(
SELECT
e = dt,
r = ROW_NUMBER() OVER (ORDER BY dt)
FROM @d
),
cte2 AS
(
SELECT
x.r,
[start] = x.e,
[end] = y.e,
m = DATEDIFF(MINUTE, x.e, y.e)
FROM cte1 AS x INNER JOIN cte1 AS y
ON x.r = y.r - 1
WHERE y.r % 2 = 0
)
SELECT
[start],
[end],
minutes_elapsed = m,
[time] = CONVERT(CHAR(8), DATEADD(MINUTE, m, 0), 108)
FROM cte2
ORDER BY [start];
Run Code Online (Sandbox Code Playgroud)
记录时间/超时的建议模式非常简单:
CREATE TABLE dbo.Shifts
(
EmployeeID INT NOT NULL, -- probably Foreign Key, right?
ClockIn DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
ClockOut DATETIME NULL
);
Run Code Online (Sandbox Code Playgroud)
现在您的查询是:
SELECT
EmployeeID,
ClockIn,
ClockOut,
ShiftLength = CONVERT(TIME(0), DATEADD(MINUTE,
DATEDIFF(MINUTE, ClockIn,
COALESCE(ClockOut, CURRENT_TIMESTAMP) -- to capture shift in progress
), 0))
FROM dbo.Shifts
WHERE ...
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
5702 次 |
最近记录: |