900*_*_db 4 sql-server aggregate window-functions date
我有一个包含一些帐户的表,以及他们的订阅的开始和结束日期。但是,这些订阅有时会重叠,我需要每个连接订阅期的开始日期和结束日期。就像示例图像中一样。
我尝试将订阅期与日期参考表合并,并标记日期(如果有订阅)。然而,代码变得相当复杂。我想一定有一个更简单的解决方案。
IF OBJECT_ID('tempdb..#Subscriptions') IS NOT NULL DROP TABLE #Subscriptions
CREATE TABLE #Subscriptions (
account_id varchar(1)
,start_date date
,end_date date
)
INSERT INTO #Subscriptions (account_id, start_date, end_date) values
('A','2019-06-20','2019-06-29'),
('A','2019-06-25','2019-07-25'),
('A','2019-07-20','2019-08-26'),
('A','2019-12-25','2020-01-25'),
('A','2021-04-27','2021-07-27'),
('A','2021-06-25','2021-07-14'),
('A','2021-07-10','2021-08-14'),
('A','2021-09-10','2021-11-12'),
('B','2019-07-13','2020-07-14'),
('B','2019-06-25','2019-08-26')
Run Code Online (Sandbox Code Playgroud)
直接地:
WITH
cte1 AS (
SELECT account_id, start_date the_date, 1 weight
FROM Subscriptions
UNION ALL
SELECT account_id, end_date, -1
FROM Subscriptions
),
cte2 AS (
SELECT account_id,
the_date,
SUM(weight) OVER (PARTITION BY account_id
ORDER BY the_date, weight DESC) weight
FROM cte1
),
cte3 AS (
SELECT account_id,
the_date,
SUM(CASE WHEN weight = 0
THEN 1
ELSE 0
END) OVER (PARTITION BY account_id
ORDER BY the_date DESC) group_no
FROM cte2
)
SELECT account_id,
MIN(the_date) start_date,
MAX(the_date) end_date
FROM cte3
GROUP BY account_id, group_no
ORDER BY 1,2
Run Code Online (Sandbox Code Playgroud)
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=82f72d57e6c527c3ce59d166c675e48c