使用 ORDER BY 从 SELECT 创建 Azure Synapse 临时表

Question

当我省略该ORDER BY子句时，或者如果我将其作为选择运行并省略创建表部分，我有以下语句，但我需要这两者来确保生成的密钥排序正确

有任何想法吗？

消息 104381​​，级别 16，状态 1，第 18 行
ORDER BY 子句在视图、CREATE TABLE AS SELECT、INSERT SELECT、SELECT INTO、内联函数、派生表、子查询和公用表表达式中无效，除非 TOP 或 FOR XML 是还指定。

CREATE TABLE #demo
WITH (DISTRIBUTION = ROUND_ROBIN)
AS
SELECT 
       ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS ID,
       schemas.name as [schema], 
       tables.name as [table], 
       columns.column_id as [ordinal],
       columns.name as [column],
       types.name as [type]
FROM SYS.COLUMNS
  inner join sys.types
          on  types.system_type_id = columns.system_type_id
  inner join sys.tables
          on  tables.object_id = columns.object_id
  inner join sys.schemas
          on  schemas.schema_id = tables.schema_id
order by schemas.name, 
       tables.name, 
       columns.column_id 

Answer 1

我想这对你有用：

CREATE TABLE #demo
WITH (DISTRIBUTION = ROUND_ROBIN)
AS
SELECT 
    ROW_NUMBER() OVER (
        ORDER BY S.[name], T.[name], C.column_id) AS ID,
    S.[name] as [schema], 
    T.[name] as [table], 
    C.[column_id] as [ordinal],
    C.[name] as [column],
    TY.[name] as [type]
FROM sys.columns AS C
JOIN sys.types AS TY
    ON TY.system_type_id = C.system_type_id
JOIN sys.tables AS T
    ON T.[object_id] = C.[object_id]
JOIN sys.schemas AS S
    ON S.[schema_id] = T.[schema_id];

关键的区别是将排序移至ROW_NUMBER窗口函数，以确定分配数字的顺序。