Ren*_*ger 7 sybase referential-integrity
我正在寻找(最好)一个 SQL 语句,该语句为任何带有外键的表选择表/和列名到 Sybase 中的给定表。我认为sys...
表格应该以某种方式可能,但对 sybase 来说是全新的,我无法理解它。因此,任何朝着正确方向发展的帮助都受到高度赞赏。
编辑:为了完整起见:SELECT @@VERSION
返回
'Adaptive Server Enterprise/15.0.3/EBF 17156 ESD#3/P/Sun_svr4/OS 5.8/ase1503/2726/64-bit/FBO/Fri Feb 5 05:26:23 2010'
编辑 2 非常
感谢您的建议,尤其是Andrew Bickerton 的评论。这使我能够构建一个基本的 SQL 选择语句,作为更进一步的起点。
如果其他人对它感兴趣,这里是:
select
fko.name "Foreign key name",
par.name "Referenced table name",
fk1.name || ' -> ' || pk1.name "Reference 1",
fk2.name || ' -> ' || pk2.name "Reference 2",
fk3.name || ' -> ' || pk3.name "Reference 3",
fk4.name || ' -> ' || pk4.name "Reference 4"
from
sysobjects tab join
sysconstraints con on tab.id = con.tableid join
sysobjects fko on con.constrid = fko.id join
sysreferences ref on con.constrid = ref.constrid join
sysobjects par on par.id = ref.reftabid left join
---- 1. Column
syscolumns fk1 on ref.fokey1 = fk1.colid and
ref.tableid = fk1.id left join
syscolumns pk1 on ref.refkey1 = pk1.colid and
ref.reftabid = pk1.id left join
---- 2. Column
syscolumns fk2 on ref.fokey2 = fk2.colid and
ref.tableid = fk2.id left join
syscolumns pk2 on ref.refkey2 = pk2.colid and
ref.reftabid = pk2.id left join
---- 3. Column
syscolumns fk3 on ref.fokey3 = fk3.colid and
ref.tableid = fk3.id left join
syscolumns pk3 on ref.refkey3 = pk3.colid and
ref.reftabid = pk3.id left join
---- 4. Column
syscolumns fk4 on ref.fokey4 = fk4.colid and
ref.tableid = fk4.id left join
syscolumns pk4 on ref.refkey4 = pk4.colid and
ref.reftabid = pk4.id -- Et cetera...
where
tab.type = 'U' and
tab.name = 'tq84_f' and
fko.type = 'RI'
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自从我在 sybase 工作以来已经有一段时间了,但是(根据记忆)以下 sql 应该为您指明正确的方向:
select *
from sysobjects so inner join syscolumns sc on so.id = sc.id
where sc.name = 'field name'
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您还可以查看sybase 在线书籍(系统表)
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