使用 GROUP BY 计算列的百分比

Question

考虑以下查询：

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SELECT\n  country\n  , count(id) AS "count"\nFROM\n  lead\nWHERE\n  date_part(\'year\', lead.since) = date_part(\'year\', CURRENT_DATE)\nGROUP BY "country"\nORDER BY "count" DESC\n;\n

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它返回类似以下内容：

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country count\nfr  3456\nus  569\nsc  248\n\xe2\x80\xa6\n

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如何添加第三列以及占总计数的百分比？

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Answer 1

SELECT country, 
       COUNT(id) "count",
       COUNT(id) / SUM(COUNT(id)) OVER () * 100 percent
FROM lead
WHERE date_part('year', lead.since) = date_part('year', CURRENT_DATE)
GROUP BY country
ORDER BY "count" DESC;