Fed*_*ust 15 sql-server-2008 sql-server pivot
假设我有表 A:BookingsPerPerson
Person_Id ArrivalDate DepartureDate
123456 2012-01-01 2012-01-04
213415 2012-01-02 2012-01-07
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我需要通过视图实现以下目标:
Person_Id ArrivalDate DepartureDate Jan-01 Jan-02 Jan-03 Jan-04 Jan-05 Jan-06 Jan-07
123456 2012-01-01 2012-01-04 1 1 1 1
213415 2012-01-02 2012-01-07 1 1 1 1 1 1
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该系统用于活动,因此每次酒店预订可能需要 1 到 15 天的时间,但不会超过此时间。任何想法将不胜感激。
Tar*_*ryn 28
您可以使用该PIVOT函数来执行此查询。我的答案将包括静态和动态版本,因为有时使用静态版本更容易理解它。
静态数据透视是您对要转换为列的所有值进行硬编码。
-- first into into a #temp table the list of dates that you want to turn to columns
;with cte (datelist, maxdate) as
(
select min(arrivaldate) datelist, max(departuredate) maxdate
from BookingsPerPerson
union all
select dateadd(dd, 1, datelist), maxdate
from cte
where datelist < maxdate
)
select c.datelist
into #tempDates
from cte c
select *
from
(
select b.person_id, b.arrivaldate, b.departuredate,
d.datelist,
convert(CHAR(10), datelist, 120) PivotDate
from #tempDates d
left join BookingsPerPerson b
on d.datelist between b.arrivaldate and b.departuredate
) x
pivot
(
count(datelist)
for PivotDate in ([2012-01-01], [2012-01-02], [2012-01-03],
[2012-01-04], [2012-01-05], [2012-01-06] , [2012-01-07])
) p;
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结果(参见SQL Fiddle With Demo):
PERSON_ID | ARRIVALDATE | DEPARTUREDATE | 2012-01-01 | 2012-01-02 | 2012-01-03 | 2012-01-04 | 2012-01-05 | 2012-01-06 | 2012-01-07
=====================================================================================================================================
123456 | 2012-01-01 | 2012-01-04 | 1 | 1 | 1 | 1 | 0 | 0 | 0
213415 | 2012-01-02 | 2012-01-07 | 0 | 1 | 1 | 1 | 1 | 1 | 1
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动态版本将生成要转换为列的值列表:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
;with cte (datelist, maxdate) as
(
select min(arrivaldate) datelist, max(departuredate) maxdate
from BookingsPerPerson
union all
select dateadd(dd, 1, datelist), maxdate
from cte
where datelist < maxdate
)
select c.datelist
into #tempDates
from cte c
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(convert(CHAR(10), datelist, 120))
from #tempDates
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT person_id, arrivaldate, departuredate, ' + @cols + ' from
(
select b.person_id, b.arrivaldate, b.departuredate,
d.datelist,
convert(CHAR(10), datelist, 120) PivotDate
from #tempDates d
left join BookingsPerPerson b
on d.datelist between b.arrivaldate and b.departuredate
) x
pivot
(
count(datelist)
for PivotDate in (' + @cols + ')
) p '
execute(@query)
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结果是一样的(参见SQL Fiddle With Demo):
PERSON_ID | ARRIVALDATE | DEPARTUREDATE | 2012-01-01 | 2012-01-02 | 2012-01-03 | 2012-01-04 | 2012-01-05 | 2012-01-06 | 2012-01-07
=====================================================================================================================================
123456 | 2012-01-01 | 2012-01-04 | 1 | 1 | 1 | 1 | 0 | 0 | 0
213415 | 2012-01-02 | 2012-01-07 | 0 | 1 | 1 | 1 | 1 | 1 | 1
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我是老派,发现CASE在我的脑海中锻炼比PIVOT. 我相信 bluefeet 很快就会出现并让我感到羞耻,但与此同时,您可以使用这个动态 SQL 查询。假设您的表存储DATE而不是DATETIME(甚至更糟,VARCHAR):
USE tempdb;
GO
CREATE TABLE dbo.a
(
Person_Id INT,
ArrivalDate DATE,
DepartureDate DATE
);
INSERT dbo.a SELECT 123456, '2012-01-01', '2012-01-04'
UNION ALL SELECT 213415, '2012-01-02', '2012-01-07';
DECLARE @sql NVARCHAR(MAX) = N'SELECT Person_Id';
;WITH dr AS
(
SELECT MinDate = MIN(ArrivalDate),
MaxDate = MAX(DepartureDate)
FROM dbo.a
),
n AS
(
SELECT TOP (DATEDIFF(DAY, (SELECT MinDate FROM dr), (SELECT MaxDate FROM dr)) + 1)
d = DATEADD(DAY, ROW_NUMBER() OVER (ORDER BY [object_id])-1,
(SELECT MinDate FROM dr))
FROM sys.all_objects
)
SELECT @sql += ',
' + QUOTENAME(d) + ' = CASE WHEN ''' + CONVERT(CHAR(10), d, 120)
+ ''' BETWEEN ArrivalDate AND DepartureDate THEN ''1'' ELSE '''' END' FROM n;
SELECT @sql += ' FROM dbo.a;'
EXEC sp_executesql @sql;
GO
DROP TABLE dbo.a;
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极少数情况之一,顺便说一句,我可以证明使用BETWEEN日期范围查询是合理的。