计算postgreSQL中2个日期之间的工作日

Question

我正在尝试计算 PostgreSQL 中某个日期范围之间的工作日。

我的桌子：

|start_date |end_date |
------------------------
|2017-06-01 |2017-06-01| 
|2017-05-29 |2017-06-02| 

这是我的代码：

SELECT pto.start_date, pto.end_date, 
SUM(CASE WHEN extract (dow FROM foo) IN(1,2,3,4,5) THEN 1 ELSE 0 END) as theDIFF 
FROM (
  SELECT start_date, (start_date::date + (generate_series(0,end_date::date 
        - start_date::date)||'days')::interval) AS foo
    FROM pto
) foo inner join pto pto
on pto.start_date = foo.start_date 
group by pto.start_date, pto.end_date

我的输出：

      |start_date(date)| end_date(date) |theDiff(integer)
      ---------------------------------------------------
      |2017-06-01      |  2017-06-01    |        29     |
      |2017-05-29      |  2017-06-02    |        12     |
      ---------------------------------------------------

预期输出：

      |start_date(date)| end_date(date) |theDiff(integer)
      ---------------------------------------------------
      |2017-06-01      |  2017-06-01    |        1      |
      |2017-05-29      |  2017-06-02    |        5      |
      ---------------------------------------------------

Answer 1

这是一个计算两个日期之间的工作日的函数，类似于网络日 Excel 公式。尚不支持假期列表。

\n\n

create or replace function count_business_days(from_date date, to_date date)\nreturns bigint\nas $fbd$\n\xc2\xa0 \xc2\xa0 select count(d::date) as d\n    from generate_series(from_date, to_date, '1 day'::interval) d\n\xc2\xa0 \xc2\xa0 where extract('dow' from d) not in (0, 6) \n$fbd$ language sql;\n

\n\n

用法

\n\n

SELECT issue_id, start_date, live_date, count_business_days(\n    TO_DATE(start_date, 'YYYY-MM-DD'),\n    TO_DATE(live_date, 'YYYY-MM-DD')\n    ) as businessdays\n    FROM atable;\n

\n

Answer 2

您没有使用（或向我们展示）唯一的键，如果您有多于一行具有相同的（开始日期，结束日期），您将得到错误的结果。

select start_date, end_date, 
       sum(case when extract (dow from dt) in (1,2,3,4,5) then 1 else 0 end) as thediff
from (
       select start_date, end_date, 
              generate_series(start_date, end_date, '1 day'::interval) as dt
       from   tbl
     ) t
group by start_date, end_date;

开始日期 | 结束日期 | 差异
:------------------ | :------------------ | ------:
2017-05-29 00:00:00 | 2017-06-02 00:00:00 | 5
2017-06-01 00:00:00 | 2017-06-01 00:00:00 | 1

select id, start_date, end_date, 
       sum(case when extract (dow from dt) in (1,2,3,4,5) then 1 else 0 end) as thediff
from (
       select id, start_date, end_date, 
              generate_series(start_date, end_date, '1 day'::interval) as dt
       from   tbl
     ) t
group by id, start_date, end_date;

编号 | 开始日期 | 结束日期 | 差异
-: | :------------------ | :------------------ | ------:
 1 | 2017-06-01 00:00:00 | 2017-06-01 00:00:00 | 1
 2 | 2017-05-29 00:00:00 | 2017-06-02 00:00:00 | 5

db<>在这里摆弄