Sch*_*ler 6 postgresql postgresql-9.6
当我在 PG 管理查询工具中尝试时,此查询对我有用:
UPDATE bankdetails SET bank_details = 'mysore' ,"PAN"= 123,bank_acc = 456,
"UAN"=789,tax = 'myy'
WHERE user_id = 79;
INSERT INTO bankdetails (user_id,bank_details,"PAN",bank_acc,"UAN",tax)
SELECT 79,'mysore',123,456,789,'myy'
WHERE NOT EXISTS (SELECT 1 FROM bankdetails WHERE user_id=79);
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后来我在我的代码中是这样实现的:
db.query('UPDATE bankdetails SET bank_details = $2 ,"PAN"= $3,bank_acc = $4,"UAN"=$5,tax = $6 WHERE user_id = $1; INSERT INTO bankdetails (user_id,bank_details,"PAN",bank_acc,"UAN",tax) SELECT $1,$2,$3,$4,$5,$6 WHERE NOT EXISTS (SELECT 1 FROM bankdetails WHERE user_id = $1);', [companyuser.rows[0]._id, data.bankDetails.bank_details, data.bankDetails.PAN, data.bankDetails.bank_acc, data.bankDetails.UAN, data.bankDetails.tax],function(err,bank) {
if (err) return callback(new Error('error'));
})
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它说:
不能在准备好的语句中插入多个命令
有人可以在这里指导我吗?
您可以使用可写 CTE 在单个查询中执行此操作:
with updated as (
UPDATE bankdetails
SET bank_details = 'mysore',
"PAN"= 123,
bank_acc = 456,
"UAN" = 789,
tax = 'myy'
WHERE bankdetails.user_id = 79
returning *
)
INSERT INTO bankdetails (user_id,bank_details,"PAN",bank_acc,"UAN",tax)
SELECT 79,'mysore',123,456,789,'myy'
WHERE NOT EXISTS (SELECT * FROM updated);
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该insert
如果将只执行update
没有更改行。
您甚至可以避免两次写入值:
with data (user_id, bank_details, pan, bank_acc, uan, tax) as (
values (79, 'mysore', 123, 456, 789, 'myy')
), updated as (
UPDATE bankdetails
SET bank_details = d.bank_details,
"PAN"= d.pan,
bank_acc = d.bank_acc,
"UAN" = d.uan,
tax = d.tax
FROM data d
WHERE user_id = d.user_id
returning *
)
INSERT INTO bankdetails (user_id,bank_details,"PAN",bank_acc,"UAN",tax)
SELECT user_id, bank_details, pan, bank_acc, uan, tax
FROM data
WHERE NOT EXISTS (SELECT * FROM updated);
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我不知道您使用的是哪种编程语言,但是对于例如 JDBC PreparedStatement,您可以values(..)
使用参数占位符替换部分中的数据:
with data (user_id, bank_details, pan, bank_acc, uan, tax) as (
values (?, ?, ?, ?, ?, ?)
)
...
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