每当我单击开始菜单中的 Ubuntu 应用程序时,我都会以 root 身份登录。有什么办法可以将默认用户设置为我创建的用户吗?
在我的 Ubuntu 18.04 中,我安装了 OpenConnect v7.08-3。但它没有 GlobalProtect 支持。OpenConnect v8.02-1 具有 GlobalProtect 支持。如何在 ubuntu 18.04 中安装它?
今天,在我运行sudo apt-get update命令后,我得到了一个NO_PUBKEY错误。我试图解决方案,从这里,这里和这里(创建文件伎俩)。尽管如此,它们都没有工作,我仍然收到以下错误:
W: GPG error: http://archive.canonical.com precise Release: The following signatures were invalid: 630239CC130E1A7FD81A27B140976EAF437D05B5
W: The repository 'http://archive.canonical.com precise Release' is not signed.
N: Data from such a repository can't be authenticated and is therefore potentially dangerous to use.
N: See apt-secure(8) manpage for repository creation and user configuration details.
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所以,特别是我在打字时得到的
sudo apt-key adv --keyserver hkp://keyserver.ubuntu.com --recv-keys 630239CC130E1A7FD81A27B140976EAF437D05B5
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是
Executing: /tmp/apt-key-gpghome.FQVhh2ndBW/gpg.1.sh --keyserver hkp://keyserver.ubuntu.com --recv-keys 630239CC130E1A7FD81A27B140976EAF437D05B5
gpg: key 40976EAF437D05B5: "Ubuntu …Run Code Online (Sandbox Code Playgroud) 我已经安装了fcrackzip. 帮助页面fcrackzip说
$ fcrackzip --h
fcrackzip version 1.0, a fast/free zip password cracker
written by Marc Lehmann <pcg@goof.com> You can find more info on*emphasized text*
http://www.goof.com/pcg/marc/
USAGE: fcrackzip
[-b|--brute-force] use brute force algorithm
[-D|--dictionary] use a dictionary
[-B|--benchmark] execute a small benchmark
[-c|--charset characterset] use characters from charset
[-h|--help] show this message
[--version] show the version of this program
[-V|--validate] sanity-check the algortihm
[-v|--verbose] be more verbose
[-p|--init-password string] use string as initial password/file
[-l|--length min-max] …Run Code Online (Sandbox Code Playgroud) 我刚刚从 Ubuntu 16.04 升级到 18.04。我的工作流程是使用 VcXsrv 从 Windows 连接到 Ubuntu(使用 X 隧道的 ssh),在 Ubuntu 上启动一个 xterm。在 xterm 中,我正在输入gnome-terminal以获得 gnome 终端。
由于升级,这不再起作用。我正进入(状态
$ gnome-terminal
# Couldn't register with accessibility bus: Did not receive a reply. Possible causes include: the remote application did not send a reply, the message bus security policy blocked the reply, the reply timeout expired, or the network connection was broken.
# Error constructing proxy for org.gnome.Terminal:/org/gnome/Terminal/Factory0: Fehler beim Aufruf von StartServiceByName für org.gnome.Terminal: Zeitüberschreitung wurde …Run Code Online (Sandbox Code Playgroud) 我想重新安装APT Tool,所以我卸载了它,然后我意识到如果我只是删除/etc/apt目录可能会更好。有什么办法可以解决我的问题吗?
我的 Ubuntu 版本是 18.04.2 LTS,输出ls /etc/apt是
root@user-OptiPlex-755:~# ls /etc/apt
ls: cannot access '/etc/apt': No such file or directory
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更新:我已经重新安装了apt,但是,这是我的输出:
root@user-OptiPlex-755:~# sudo apt install --reinstall apt-utils ubuntu-minimal ubuntu-release-upgrader-gtk ubuntu-desktop update-manager update-notifier update-notifier-common
Reading package lists... Done
Building dependency tree
Reading state information... Done
Package update-manager is not available, but is referred to by another package.
This may mean that the package is missing, has been obsoleted, or
is only available from another source …Run Code Online (Sandbox Code Playgroud) 我的 Ubuntu 安装抱怨内存不足。所以我把上学期的一些旧学校文件移走了,重新启动,现在每次我开始时它都会挂在这上面。我只是尝试等待,因为谷歌表明它需要更多时间或熵,所以我尝试随机按键并移动鼠标,但什么也没发生。
我该如何摆脱这个问题并启动我的 Ubuntu?
我试图让我的脚本在 20 到 10 秒之间随机暂停,其中最大时间为 20 秒,最小时间为 10 秒。我正在使用这个 atm:
sleep $((10 + RANDOM % 20));
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但问题是它忽略了 20 的限制并超出了这个限制。还有其他方法吗?
计算机重新启动后,Windows 10 上新安装的 Ubuntu 子系统向我展示了
Access is denied.
Press any key to continue...
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有什么解决办法吗?
执行时出错
sudo apt upgrade
sudo apt upgrade
Reading package lists... Done
Building dependency tree
Reading state information... Done
You might want to run 'apt --fix-broken install' to correct these.
The following packages have unmet dependencies:
libpulsedsp : Depends: libpulse0 (= 1:13.99.1-1ubuntu3.6) but 1:13.99.1-1ubuntu3.7 is installed
pulseaudio : Depends: libpulse0 (= 1:13.99.1-1ubuntu3.6) but 1:13.99.1-1ubuntu3.7 is installed
pulseaudio-module-bluetooth : Depends: libpulse0 (= 1:13.99.1-1ubuntu3.6) but 1:13.99.1-1ubuntu3.7 is installed
E: Unmet dependencies. Try 'apt --fix-broken install' with no packages (or specify a solution).
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输入后出现 …