我得到如下 curl 命令输出
curl -s https://api.github.com/repos/harshavardhanc/dockerfile-ansible/pulls\?state\=all | jq -r '.[]|(.number|tostring)+" "+.user.login+" "+.created_at+" "+.merged_at'
5 test 2019-09-27T11:06:23Z 2019-09-27T11:09:28Z
4 test1 2019-09-26T16:56:40Z 2019-09-26T16:57:02Z
3 test2 2019-09-26T16:54:25Z 2019-09-26T16:54:55Z
2 test3 2019-09-26T16:52:59Z 2019-09-26T16:55:19Z
1 test4 2019-09-26T16:46:52Z 2019-09-26T16:47:25Z
我将它存储在一个变量中，并尝试通过 echo 变量将值传递给另一个命令来解析输出。但是当我尝试回显变量时，它将所有行打印为一行。
prlist=$(curl -s https://api.github.com/repos/harshavardhanc/dockerfile-ansible/pulls\?state\=all | jq -r '.[]|(.number|tostring)+" "+.user.login+" "+.created_at+" "+.merged_at')
echo $prlist
5 test 2019-09-27T11:06:23Z 2019-09-27T11:09:28Z 4 test1 2019-09-26T16:56:40Z 2019-09-26T16:57:02Z 3 test2 2019-09-26T16:54:25Z 2019-09-26T16:54:55Z 2 test3 2019-09-26T16:52:59Z 2019-09-26T16:55:19Z1 test4 2019-09-26T16:46:52Z 2019-09-26T16:47:25Z
如何避免这种打印在不同的行？请帮忙。