获取特殊字符模式之间的行

Question

下面是我的输入文件：

---
{
  "date":"2015-09-24",
  "title":"Getting Started with Git",
  "template":"post",
  "thumbnail":"content/thumbnails/test.jpeg",
  "slug":"getting-started-with-git",
  "categories":[ "cat1", "Focus", "Mustang" ],
  "tags":[ "Fiesta", "Focus", "Mustang" ]
}
---

#Hello

---
This is sample
---

```
var x=1;
entry.forEach(function(item){
    x=x++;
})
```

我在输出中期望的是，前2行之间的' --- '

{
  "date":"2015-09-24",
  "title":"Getting Started with Git",
  "template":"post",
  "thumbnail":"content/thumbnails/test.jpeg",
  "slug":"getting-started-with-git",
  "categories":[ "cat1", "Focus", "Mustang" ],
  "tags":[ "Fiesta", "Focus", "Mustang" ]
}

我怎样才能实现它？使用awk，只有当我将 ' --- '替换为诸如 'start'/'end' 之类的字符串时，我才能实现这一点。

awk '/start/{f=1;next} /end/{f=0;exit} f'  $FILE_PATH

Answer 1

这是一种解决方案：

awk '/^---/ {mark++; next} mark == 1 {print}' $FILE_PATH

其中产生：

{
  "date":"2015-09-24",
  "title":"Getting Started with Git",
  "template":"post",
  "thumbnail":"content/thumbnails/test.jpeg",
  "slug":"getting-started-with-git",
  "categories":[ "cat1", "Focus", "Mustang" ],
  "tags":[ "Fiesta", "Focus", "Mustang" ]
}

mark每次遇到该---行时，都会增加一个命名的变量。我们只在mark == 1. 这是一个很好的解决方案，因为它可以让您提取任意的---分隔文本块。也就是说，如果我们想要第二块---分隔文本，我们可以运行：

awk '/^---/ {mark++; next} mark == 2 {print}' $FILE_PATH

这给了我们：

#Hello