Lil*_*lia 5 command-line grep text-processing
随着systemctl status name.service | grep Active
我得到这个信息:
Active: active (running) since Mon 2018-05-14 21:44:09 CEST; 5s ago
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我怎样才能获得相同的信息但没有:“活动:”?
您可以使用
grep -oP 'Active: \K.*'
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打印没有“Active:”的行:
$ systemctl status ssh.service | grep Active
Active: active (running) since Sat 2018-03-31 14:15:07 CEST; 1 months 13 days ago
$ systemctl status ssh.service | grep -oP 'Active: \K.*'
active (running) since Sat 2018-03-31 14:15:07 CEST; 1 months 13 days ago
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-o
告诉grep
只打印匹配行的匹配部分-P
启用 Perl 兼容的正则表达式 (PCRE),这是需要使用的\K
,它使匹配的文本远离整体正则表达式匹配。