多个文件文本替换为 sed

Question

我尝试将文本文件中的某些文本替换为 ，sed但不知道如何使用多个文件进行替换。
我用：

sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g /path/to/file/target_text_file

在我使用多个文件之前，我使用以下命令在文本文件中打印了目标文本文件的路径：

find /path/to/files/ -name "target_text_file" > /home/user/Desktop/target_files_list.txt

现在我想sed按照target_files_list.txt.

Answer 1

您可以使用循环遍历文件while ... do：

$ while read i; do printf "Current line: %s\n" "$i"; done < target_files_list.txt

在你的情况下，你应该printf ...用sed你想要的命令替换。

$ while read i; do sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g' "$i"; done < target_files_list.txt

但是，请注意，您可以仅使用以下内容来实现您想要的find：

$ find /path/to/files/ -name "target_text_file" -exec sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g' {} \;

您可以-exec通过运行来阅读有关选项的更多信息man find | less '+/-exec '：

   -exec command ;

          Execute command; true if 0 status is returned.  All
          following arguments to find are taken to be arguments to
          the command until an argument consisting of `;' is
          encountered.  The string `{}' is replaced by the current
          file name being processed everywhere it occurs in the
          arguments to the command, not just in arguments where it
          is alone, as in some versions of find.  Both of these
          constructions might need to be escaped (with a `\') or
          quoted to protect them from expansion by the shell.  See
          the EXAMPLES section for examples of the use of the
          -exec option.  The specified command is run once for
          each matched file.  The command is executed in the
          starting directory.  There are unavoidable security
          problems surrounding use of the -exec action; you should
          use the -execdir option instead.

编辑：

由于正确地指出用户 terdon和甜品中有必要使用意见-r用read，因为它会正确处理反斜杠。它也被报道shellcheck：

$ cat << EOF >> do.sh
#!/usr/bin/env sh
while read i; do printf "$i\n"; done < target_files_list.txt
EOF
$ ~/.cabal/bin/shellcheck do.sh

In do.sh line 2:
while read i; do printf "\n"; done < target_files_list.txt
      ^-- SC2162: read without -r will mangle backslashes.

所以应该是：

$ while read -r i; do sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g' "$i"; done < target_files_list.txt