如何在 Ubuntu 服务器 16.04 中以特定用户启动后启动 Zookeeper 守护进程

Question

我想在 Ubuntu 服务器 16.04 启动后（而不是登录后）在名为Zookeeper的用户下启动 Zookeeper 守护进程。所以我改变了文件/etc/rc.local如下：

#!/bin/sh -e
#
# rc.local
#
# This script is executed at the end of each multiuser runlevel.
# Make sure that the script will "exit 0" on success or any other
# value on error.
#
# In order to enable or disable this script just change the execution
# bits.
#
# By default this script does nothing.

echo 'never'; defrag_file_pathname

su -c '$ZOOKEEPER_HOME/bin/zkServer.sh start' zookeeper &

exit 0

su -c '$ZOOKEEPER_HOME/bin/zkServer.sh start' zookeeper &，在 之前添加行exit 0。但重启后进程并没有启动！

这是怎么回事？

详细信息：zookeeper用户位于sudo组中并且有密码。

详细信息：当我su -c '$ZOOKEEPER_HOME/bin/zkServer.sh start' zookeeper &在终端中运行命令时，它需要密码才能运行。

Answer 1

创建一个 。service文件/etc/systemd/system/zoo.service并添加以下行：

[Unit]
Description=Zookeeper Daemon
Wants=syslog.target

[Service]    
Type=forking
WorkingDirectory=/path/to/dir/of/interest
User=zookeeper 
ExecStart=/home/zookeeper_home/bin/zkServer.sh
TimeoutSec=30
Restart=on-failure

[Install]
WantedBy=multi-user.target

现在设置服务：

sudo systemctl start zoo
sudo systemctl enable zoo

检查状态：

sudo systemctl status zoo

请阅读创建守护进程的更多详细信息：

https://www.freedesktop.org/software/systemd/man/systemd.unit.html