检查输入以查看它是“y”、“n”还是其他的 bash 脚本 - 不工作

Question

我已经编写了这个 bash 脚本，它旨在检查您的输入以查看它是否是y，n或其他内容（这将是更大项目的一部分）：

#!/bin/bash

echo "Have you updated the PATH variable in your .bashrc file yet? [y/n]"
read response

        if [$response = "y"]; then
                echo "Checkpoint passed"
                set $checkpoint = "t"
        elif [$response = "n"]; then
                echo "Please set the PATH variable in your .bashrc file before running this script."
                set $checkpoint = "f"
        else            
                echo "Please only use 'y' and 'n'."
                set $checkpoint = "f"
        fi

但是每次运行它时，无论我输入什么，都会收到与此类似的错误：

Have you updated the PATH variable in your .bashrc file yet? [y/n]
y
./snbjdkhome: line 6: [y: command not found
./snbjdkhome: line 9: [y: command not found
Please only use 'y' and 'n'.

那么我的代码有什么问题？（我对 shell 脚本很陌生。）

Answer 1

这会让你清楚（检查空格）：

$ var=c

$ ["$var" == "c"] && echo "OK"
[c: command not found

$ ["$var" == "c" ] && echo "OK"
[c: command not found

$ [ "$var" == "c"] && echo "OK"
bash: [: missing `]'

$ [ "$var" == "c" ] && echo "OK"
OK

因此，在使用test( [ ]) 命令时，您需要在条件前后放置空格。